(3x-5)^2=(2x-3)(3x-5)

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Solution for (3x-5)^2=(2x-3)(3x-5) equation: 



(3x-5)^2=(2x-3)(3x-5)

We move all terms to the left:

(3x-5)^2-((2x-3)(3x-5))=0

We multiply parentheses ..

-((+6x^2-10x-9x+15))+(3x-5)^2=0



We calculate terms in parentheses: -((+6x^2-10x-9x+15)), so:

(+6x^2-10x-9x+15)

We get rid of parentheses

6x^2-10x-9x+15

We add all the numbers together, and all the variables

6x^2-19x+15

Back to the equation:

-(6x^2-19x+15)



We get rid of parentheses

-6x^2+19x+(3x-5)^2-15=0

We move all terms containing x to the left, all other terms to the right

-6x^2+19x+(3x-5)^2=15

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